Thanx Thomas very much for link to PDF file "Using ConTEXt with Databases". I'm sure I will use it in the future. Jaroslav Hajtmar Dne 20.2.2014 13:57, Thomas A. Schmitz napsal(a):

On 02/20/2014 01:22 PM, Xan wrote:

...

If you comment one solution, then, you get "Answer to question 1", instead of "Answer of question 2", which is really. No always a question has an answer provided by me;-)

Thanks,

Obviously you will have to give every question|answer|hint some sort of unique identifier to which you can later refer. So an enumeration is maybe not the best approach for this because these identifiers need to be shared between all your blocks.

Just a personal impression: if you want to have many of these blocks, I would advise to use some format other than TeX to store them because it soon becomes difficult to read for you and unsustainable. I have written something in MAPS (http://www.ntg.nl/maps/42/12.pdf) which may be useful for you.

Thomas ___________________________________________________________________________________

If your question is of interest to others as well, please add an entry to the Wiki!

maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________

Thanx Wolfgang. For me this is valuable information Jaroslav Hajtmar Dne 20.2.2014 14:13, Wolfgang Schuster napsal(a):

Am 20.02.2014 um 13:22 schrieb Xan :

...

Not exactly. If you don't have the same number of answers that the number of questions, so your counter is not properly set. See that:

\defineblock[question] \defineblock[hint] \defineblock[answer]

\defineenumeration[question][alternative=hanging,width=2.5cm,text={Question},stopper={.}] \defineenumeration[hint] [alternative=hanging,width=4cm,text={Hint for question},stopper={.}] \defineenumeration[answer] [alternative=hanging,width=4.5cm,text={Answer to question},stopper={.}]

\keepblocks[question] \hideblocks[hint] \hideblocks[answer]

\starttext

\section{Questions}

\beginquestion \startquestion Compute $4\times 5$. \stopquestion \endquestion

\beginhint \starthint Use the fact that $2\times 5 = 10$. \stophint \endhint

%\beginanswer %\startanswer % $20$. %\stopanswer %\endanswer

\beginquestion \startquestion What is the value of $100/10$? \stopquestion \endquestion

\beginhint \starthint Remember that $10\times 10 = 100$. \stophint \endhint

\beginanswer \startanswer $10$ \stopanswer \endanswer

\section{Hints}

\useblocks[hint]

\section{Answers}

\useblocks[answer]

\stoptext

If you comment one solution, then, you get "Answer to question 1", instead of "Answer of question 2", which is really. No always a question has an answer provided by me ;-)

You can add a answer block which increments the answer counter.

\defineblock[question] \defineblock[answer]

\defineenumeration[question][text={Question}] \defineenumeration[answer] [text={Answer}]

\keepblocks[question] \hideblocks[answer]

\starttext

\chapter{Question}

\beginquestion \startquestion Question 1. \stopquestion \endquestion

\beginanswer \startanswer Answer 1. \stopanswer \endanswer

\beginquestion \startquestion Question 2. \stopquestion \endquestion

\beginanswer \incrementcounter[answer] \endanswer

\beginquestion \startquestion Question 3. \stopquestion \endquestion

\beginanswer \startanswer Answer 3. \stopanswer \endanswer

\chapter{Answers}

\useblocks[answer]

\stoptext

Wolfgang ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki!

maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________

No, it does not work. I have this: % Questions \defineenumeration [exercici] [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}] % Answers \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no] \defineblock[resposta] \hideblocks[resposta] % Exercises \startexercici Bla... \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \startexercici Bla 2 \stopexercici \startexercici Bla 3 \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \subject{Answers} \selectblocks[resposta][criterium=section] I get \getnumber[exercici] as the last, not the counter of 'exercici' in which I have the answer. How can I do thaT? Thanks,

Am 22.02.2014 um 18:45 schrieb Xan <dxpublica at telefonica.net>:

...

No, it does not work.

I have this:

% Questions \defineenumeration [exercici] [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}]

% Answers \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no]

\defineblock[resposta] \hideblocks[resposta]

% Exercises

\startexercici Bla... \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici

\startexercici Bla 2 \stopexercici

\startexercici Bla 3 \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici

\subject{Answers}

\selectblocks[resposta][criterium=section]

I get \getnumber[exercici] as the last, not the counter of 'exercici' in which I have the answer. How can I do thaT?

Make a complete minimal example.

Wolfgang

Simply put starttext and stoptext. Here it's: % Questions \defineenumeration [exercici] [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}] % Answers \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no] \defineblock[resposta] \hideblocks[resposta] % Exercises \starttext \startexercici Bla... \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \startexercici Bla 2 \stopexercici \startexercici Bla 3 \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \subject{Answers} \selectblocks[resposta][criterium=section] \stoptext Can you help me? Thanks,

...

Can you help me?

Your counter settings are useless because context stores only the environment plus content for the answers, nothing is done with them at this point. When you flush the answer blocks context sees them for the first time and the counter for the questions is 3 at this point and this is why you get always the same value.

Is there any way of first evaluate \getnumber[exercici] and then store the content, and not inversely (as context does now)?

\defineenumeration[exercici][text=Exercici] \defineenumeration[resposta][text=Solucions]

\defineblock[resposta] \hideblocks[resposta]

\starttext

\startexercici Question 1 \beginresposta \resposta Answer 1 \par \endresposta \stopexercici

\startexercici Question 2 \beginresposta \incrementcounter[resposta] \endresposta \stopexercici

\startexercici Question 3 \beginresposta \resposta Answer 3 \par \endresposta \stopexercici

\subject{Answers}

\selectblocks[resposta]

\stoptext

Wolfgang

Increment counter *every* time is possible option, but in fact very annoying: if I have 100 exercises (now I have more than this) and I have only 20 exercises, then I have to put "\incrementcounter" in 80 exercises. It's a tedious thing. Is there any more "relaxing" thing: assuming that I have 'resposta' nested in 'exercici' like \startexercici \beginresposta \resposta Answer X \endresposta \stopexercici ? Thanks another time, Xan